$RbO_2$ means $Rb^+ O^-_2$ and ion. $O^-_2$ ion is super oxide ion. It has 17 electrons and is paramagnetic.
So, the correct answer is (C): Super oxide and paramagnetic
RbO2 is the rubidium superoxide. In this the Rb is present in +1 oxidation state and oxygen is -1.
RbO2 is an unstable and reactive compound that can be formed with the reaction between rubidium and oxygen.
The compound has unpaired electrons therefore they are paramagnetic in nature.
So, the correct answer is (C): Super oxide and paramagnetic
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Consider the following statements: Statement I: \( 5 + 8 = 12 \) or 11 is a prime. Statement II: Sun is a planet or 9 is a prime.
Which of the following is true?
The value of \[ \int \sin(\log x) \, dx + \int \cos(\log x) \, dx \] is equal to
The value of \[ \lim_{x \to \infty} \left( e^x + e^{-x} - e^x \right) \] is equal to