$RbO_2$ means $Rb^+ O^-_2$ and ion. $O^-_2$ ion is super oxide ion. It has 17 electrons and is paramagnetic.
So, the correct answer is (C): Super oxide and paramagnetic
RbO2 is the rubidium superoxide. In this the Rb is present in +1 oxidation state and oxygen is -1.
RbO2 is an unstable and reactive compound that can be formed with the reaction between rubidium and oxygen.
The compound has unpaired electrons therefore they are paramagnetic in nature.
So, the correct answer is (C): Super oxide and paramagnetic
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is