Let a, b, and c be the daily work units completed by Rahul, Rakshita, and Gurmeet, respectively. The total work units would be W.
Therefore, we can conclude that \(7(a+b+c) < W\) (because Rahul, Rakshita, and Gurmeet would have needed more than 7 days to complete a task if they had worked together).
Similar to this, we can state that \(15(a+c) > W\), meaning that Rahul and Gurmeet could have completed the task in less than 15 days if they had collaborated.
Now, when we contrast these two inequalities, we obtain: \(15(a+c) < W < 7(a+b+c) \)
It is also reported that Rakshita worked alone for three more days to complete the task after they had all collaborated for six days. \(W = 6(a+b+c)+3b\) represents the total amount of work completed.
Thus, we can state that \(6(a+b+c)+3b < 15(a+c) = 7(a+b+c).\)
\(A+b+c < 3b\)
\(⇒ 7(a+b+c) < 21b,\) and \(15b < 15(a+c) \) imply that \((a+b+c) < 3b\)
\(⇒ a+c < 2b\) and \(9b < 9(a+c)\)
\( ⇒ b < a+c.\)
Therefore, the days needed for B must fall between 15 and 21 (inclusive).
Therefore, choice B is the right one.