Question:

Radius of gyration of disc of mass 50 g and radius 2.5 cm about an axis passing through its center of gravity and perpendicular to the plane is

Updated On: Dec 18, 2023
  • 6.54 cm
  • 3.64 cm
  • 1.77 cm
  • 0.88 cm
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Here mass M = 50 g and radius R = 2.5 cm Required moment of inertia of the disc is given by $I=\frac{MR^2}{2}=MK^2$ so,$K^2=\frac{R^2}{2}or \, K=\frac{R}{\sqrt{2}}=\frac{2.5}{\sqrt{2}}=\frac{2.5\sqrt{2}}{2}$ = 1.767= 1.77 cm
Was this answer helpful?
1
0

Top Questions on rotational motion

View More Questions

Concepts Used:

Rotational Motion

Rotational motion can be defined as the motion of an object around a circular path, in a fixed orbit.

Rotational Motion Examples:

The wheel or rotor of a motor, which appears in rotation motion problems, is a common example of the rotational motion of a rigid body.

Other examples:

  • Moving by Bus
  • Sailing of Boat
  • Dog walking
  • A person shaking the plant.
  • A stone falls straight at the surface of the earth.
  • Movement of a coin over a carrom board 

Types of Motion involving Rotation:

  1. Rotation about a fixed axis (Pure rotation)
  2. Rotation about an axis of rotation (Combined translational and rotational motion)
  3. Rotation about an axis in the rotation (rotating axis)