Question:

Pune taxi services has a fixed charge plus a variable charge based on the distance covered. For travelling 10km the total fare paid by Somu is Rs.150 and for a journey of 15km the total fare paid by Ramu is RS220. Then Tomy will pay _as the total fare for travelling a distance of 25 km.

Updated On: Oct 4, 2024
  • Rs. 350
  • Rs. 380
  • Rs. 360
  • Rs. 400
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The Correct Option is C

Solution and Explanation

Let's denote the fixed charge as \( F \) and the variable charge per kilometer as \( V \).
Given:
1. For traveling 10 km, Somu pays Rs. 150:
\[ F + 10V = 150 \]
2. For traveling 15 km, Ramu pays Rs. 220:
\[ F + 15V = 220 \]
We have two linear equations:
\[ F + 10V = 150 \]
\[ F + 15V = 220 \]
To find \( F \) and \( V \), subtract the first equation from the second:
\[ (F + 15V) - (F + 10V) = 220 - 150 \]
\[ 5V = 70 \]
\[ V = 14 \]
Now, substitute \( V \) back into the first equation to find \( F \):
\[ F + 10(14) = 150 \]
\[ F + 140 = 150 \]
\[ F = 10 \]
Now that we have \( F \) and \( V \), we can find the total fare for Tomy who travels 25 km:
\[ F + 25V = 10 + 25(14) \]
\[ F + 25V = 10 + 350 \]
\[ F + 25V = 360 \]
Thus, Tomy will pay Rs. 360 for traveling 25 km.
Answer: C Rs. 360
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