For the given cell: Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s) {Fe}^{2+}(aq) + {Ag}^+(aq) \to {Fe}^{3+}(aq) + {Ag}(s) Fe2+(aq)+Ag+(aq)→Fe3+(aq)+Ag(s) The standard cell potential of the above reaction is given. The standard reduction potentials are given as: Ag++e−→AgE∘=x V {Ag}^+ + e^- \to {Ag} \quad E^\circ = x \, {V} Ag++e−→AgE∘=xV Fe2++2e−→FeE∘=y V {Fe}^{2+} + 2e^- \to {Fe} \quad E^\circ = y \, {V} Fe2++2e−→FeE∘=yV Fe3++3e−→FeE∘=z V {Fe}^{3+} + 3e^- \to {Fe} \quad E^\circ = z \, {V} Fe3++3e−→FeE∘=zV The correct answer is: