Step 1: Identify the given polynomial.
The given polynomial is \( 5x^2 - 1 \).
Step 2: Recognize the standard form of a quadratic polynomial.
The general form is: \( ax^2 + bx + c \)
Comparing: \( a = 5 \), \( b = 0 \), \( c = -1 \)
Step 3: Use the formula for product of zeroes of a quadratic polynomial.
The formula is:
\[ \text{Product of zeroes} = \frac{c}{a} \]
Step 4: Substitute the values.
\[ \text{Product of zeroes} = \frac{-1}{5} = -\frac{1}{5} \]
So, the product of the zeroes of the polynomial \( 5x^2 - 1 \) is \( -\frac{1}{5} \).
Let \( M \) be a \( 7 \times 7 \) matrix with entries in \( \mathbb{R} \) and having the characteristic polynomial \[ c_M(x) = (x - 1)^\alpha (x - 2)^\beta (x - 3)^2, \] where \( \alpha>\beta \). Let \( {rank}(M - I_7) = {rank}(M - 2I_7) = {rank}(M - 3I_7) = 5 \), where \( I_7 \) is the \( 7 \times 7 \) identity matrix.
If \( m_M(x) \) is the minimal polynomial of \( M \), then \( m_M(5) \) is equal to __________ (in integer).
In the given figure, graph of polynomial \(p(x)\) is shown. Number of zeroes of \(p(x)\) is
