The reaction shown indicates the process of hydrolysis and reduction of boranes. When B4H6 reacts with water and sodium hydroxide, it undergoes hydrolysis to produce alcohols and alkanes.
Understanding the Reactions: B4H6 is a borane compound, and its reaction with water in the presence of a base leads to the formation of organic products. The primary reactions involve the cleavage of the B-H bonds and subsequent formation of C-H and C-O bonds.
Products Formed: From the reaction conditions, it is clear that the product A formed from the hydrolysis will likely be a simple alcohol (such as methanol), while product B will be the corresponding alkane (like methane).
Thus, the correct identification of products A and B leads to: A = CH3, B = CH2OH
\( \text{M} \xrightarrow{\text{CH}_3\text{MgBr}} \text{N} + \text{CH}_4 \uparrow \xrightarrow{\text{H}^+} \text{CH}_3\text{COCH}_2\text{COCH}_3 \)
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