Question:
Potassium manganate $(K_2MnO_4)$ is formed when
Potassium manganate $(K_2MnO_4)$ is formed when
Updated On: Jun 14, 2022
- chlorine is passed into aqueous $KMnO_4$ solution
- manganese dioxide is fused with KOH in air
- formaldehyde reacts with potassium permanganate in the presence of strong alkali
- potassium permanganate reacts with cone. H$_2SO_4$
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The Correct Option is C
Solution and Explanation
$2KOH + MnO_2 +O_2 \underrightarrow{\Delta} K_2MnO_4+H_2O$
$HCHO +KMnO_4 \rightarrow K_2MnO_4 + H_2O$
$\hspace40mm +HCOOH$
$HCHO +KMnO_4 \rightarrow K_2MnO_4 + H_2O$
$\hspace40mm +HCOOH$
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Concepts Used:
Preparation
Preparation of Aldehydes:
- In the presence of palladium catalyst spread on barium sulfate, Acid chlorides are reduced to aldehydes with hydrogen .
- This is known as Rosenmund reduction. It is mostly used for the preparation of aromatic aldehydes.
Preparation of Ketones:
- Acid chlorides on reaction with dialkyl cadmium form ketones. Grignard reagents are used in the preparation of Dialkyl cadmium.
- 2R-Mg-X + CdCl2 → R2Cd + 2 Mg(X)Cl
- 2RCOCl + R2Cd → 2R-CO-R + CdCl2
- The mixed ketones are prepared very conveniently.
Preparation of Carboxylic Acids:
- Primary alcohols are readily oxidized to carboxylic acids with common oxidizing agents such as potassium permanganate in neutral acidic or alkaline media or by potassium dichromate and chromium trioxide in acidic media.
- RCH2OH → RCOOH
- CH3(CH2)8CH2OH → CH3(CH2)8COOH
Read More: Aldehydes, Ketone, and Carboxylic Acids