Question:

Particular integral of the partial differential equation \( \frac{\partial^2 z}{\partial x^2} - 2 \frac{\partial^2 z}{\partial x \partial y} + \frac{\partial^2 z}{\partial y^2} = 2x \cos y \) is

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Use operator methods for PDEs with constant coefficients. Recognize forms like \( (D - D')^2 \) and apply inverse operators accordingly.
Updated On: May 4, 2025
  • \( x \cos y + 2 \sin y \)
  • \( -2(x \cos y + 2 \sin y) \)
  • \( 2 \cos y + x \sin y \)
  • \( 2 \cos y + \sin y \)
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The Correct Option is B

Solution and Explanation

We simplify the operator: \[ \frac{\partial^2 z}{\partial x^2} - 2 \frac{\partial^2 z}{\partial x \partial y} + \frac{\partial^2 z}{\partial y^2} = (D - D')^2 z = 2x \cos y \] Now solve using operator method: \[ (D - D')^2 z = 2x \cos y \] Let \( z = P.I. = -2(x \cos y + 2 \sin y) \), as derived from standard methods of solving linear PDEs with constant coefficients.
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