List of practice Questions

When a current flows through a conductor, there will be increase in temperature. This is mainly due to

Two sources of equal emf are connected to an external resistance $R$. The internal resistances of the two sources are $R_1$ and $R_2 (R_2 > R_1).$ If the potential difference across the source having internal resistance $R_2$, is zero, then :

Two voltameters, one of copper and another of silver, are joined in parallel. When a total charge $q$ flows through the voltameters, equal amount of metals are deposited. If the electrochemical equivalents of copper and silver are $Z_1$ and $Z_2$ respectively, the charge which flows through the silver voltameter is :

An energy source will supply a constant current into the load, if its internal resistance is :

If an ammeter is to be used in place of a voltmeter, then we must connect with the ammeter a:

A wire when connected to 220V mains supply has power dissipation $ {{P}_{1}} $ . Now the wire is cut into two equal pieces which are connected in parallel to the same supply. Power dissipation in this case is $ {{P}_{2}} $ . Then $ {{P}_{2}}:{{P}_{1}} $ is

The resistance of hot tungsten filament is about $10$ times the cold resistance. What will be the resistance of $100\, W$ and $200\, V$ lamp, when not in use ?

The resistors are connected as shown in the figure below. Find the equivalent resistance between the points A and B.

Two concentric circular loops of radii $0.08 \, m$ and $0.1 \, m$ carry currents such that magnetic field at the centre is zero. If the current in the outer loop is $8 \, A$ clockwise, current in the inner loop is

$Na _{2} S _{2} O _{3}+ I _{2} \longrightarrow$ Product is

$50 \,mL$ of $10 \,N H_2SO_4, 25 \,mL$ of $12 \,N \,HCI$ and $40\, mL$ of $5N \,HNO_3$ are mixed and the volume of the mixture is made $1000\, mL$ by adding water. The normality of resulting solution will be

How will you separate a solution (miscible) of benzene $ +CHCl_{3}$ ?

Formalin is:

A particle on trough of a wave at any instant will come to mean position after time (T=time period)

A particle is executing the motion $ x=a\,\cos (\omega t-\theta ). $ The velocity of the particle is:

A simple pendulum has time period $T_1$. The point of suspension is now moved upward according to the relation $y = kt^2, (k = 1ms^{-2})$ where y is the vertical displacement. The time period now becomes $T_2$. The ratio of $\frac{T^2_1}{T^2_2}$ is $(Take\,g = 10ms^{-2})$

Two simple pendulums whose lengths are $100\, cm$ and $121\, cm$ are suspended side by side. Their bobs are pulled together and then released. After how many minimum oscillations of the longer pendulum, will be the two be in phase again?

A body executing SHM has its velocity $10\, cm/s$ and $7\, cm/s$, when its displacements from the mean position are $3\, cm$ and $4 \,cm$, respectively The length of path is :

The displacement of a particle performing simple harmonic motion is given by, x=8sin$\omega t+6cos \omega t$, where distance is in cm and time is in second. The amplitude of motion is

The minimum phase difference between two simple harmonic oscillations, $ \, \, \, \, \, \, \, \, y_1 =\frac{1}{2}sin \omega t +\frac{\sqrt 3}{2} cos \omega t$ $ \, \, \, \, \, \, \, \, \, \, \, y_2 =sin \omega t +cos \omega t$ is

Consider the following statements : The total energy of a particle executing simple harmonic motion depends on its : (I) amplitude (II) period (III) displacement Of these statements :

The maximum velocity of a simple harmonic motion represented by $ y=3\sin \left( 100\,t+\frac{\pi }{6} \right)m $ is given by:

A particle executing SHM has amplitude $0.01$ and frequency $60\, Hz$. The maximum acceleration of the particle is: