Negation of \( p \land (q \land \neg (p \land q)) \) is:}
To find the negation of the statement (¬p∧q)∨(p∧¬q), we will follow the steps of logical negation and apply De Morgan's laws.
1. Write down the original statement:
S=(¬p∧q)∨(p∧¬q)
2. Apply negation to the entire statement:
¬S=¬((¬p∧q)∨(p∧¬q))
3. Use De Morgan's Law: According to De Morgan's laws, the negation of a disjunction is the conjunction of the negations:
¬S=¬(¬p∧q)∧¬(p∧¬q)
4. Apply De Morgan's Law to each part:
¬(¬p∧q)=¬(¬p)∨¬(q)=p∨¬q
¬(p∧¬q)=¬(p)∨¬(¬q)=¬p∨q
5. Combine the results:
¬S=(p∨¬q)∧(¬p∨q)
6. Final expression:
The negation of the original statement is: ¬S=(p∨¬q)∧(¬p∨q)
A force \( \vec{f} = x^2 \hat{i} + y \hat{j} + y^2 \hat{k} \) acts on a particle in a plane \( x + y = 10 \). The work done by this force during a displacement from \( (0,0) \) to \( (4m, 2m) \) is Joules (round off to the nearest integer).