Question

$P_4\text{O}_\text{10} \text{H}_2\text{O} \xrightarrow{\text{X}} \xrightarrow{\text{Y}} \text{The number of P-OH, P=O bonds in Y is respectively}$ 

• A. 2, 4
• B. 4, 2
• C. 3, 1
• D. 3, 3

Hint:

Phosphoric acid (\( \text{H}_3\text{PO}_4 \)) contains 4 hydroxyl groups (P-OH) and 2 phosphoryl groups (P=O).

Answer 1

The Correct Option is B

- The chemical reaction described seems to be referring to the transformation of \( \text{P}_4\text{O}_{10} \), possibly involving the formation of phosphoric acid (\( \text{H}_3\text{PO}_4 \)) from the reaction with water.
- In the product Y (phosphoric acid), the number of P-OH bonds (hydroxyl groups) and P=O bonds (phosphoryl groups) must be counted.
- Phosphoric acid has 4 P-OH bonds and 2 P=O bonds, so the correct answer is 4 P-OH bonds and 2 P=O bonds.
Thus, the correct answer is (2) 4, 2.