Step 1: Understanding the Given Reaction
We are given the following reaction:
\( 2 \, \text{ClO}_2 + 2 \, \text{O}_3 \rightarrow \text{Cl}_2\text{O}_6 + 2 \, \text{O}_2 \)
This reaction shows chlorine dioxide (ClO2) reacting with ozone (O3) to give dichlorine hexoxide (Cl2O6) and oxygen gas (O2).
Step 2: Paramagnetism of ClO2
ClO2 contains an odd electron, which makes it paramagnetic. This is because it has an unpaired electron in its molecular orbitals, which causes it to be attracted to magnetic fields.
Step 3: Oxidation States of Chlorine in ClO2 and Cl2O6
To determine the oxidation state of chlorine in the given compounds, we need to consider the oxidation state of oxygen (which is typically -2 in most compounds) and apply the rules for calculating oxidation states.
- In ClO2, oxygen has an oxidation state of -2. Since the compound is neutral overall, we can use the equation to determine the oxidation state of chlorine:
\[
x + 2(-2) = 0 \quad \Rightarrow \quad x - 4 = 0 \quad \Rightarrow \quad x = +4
\]
So, the oxidation state of chlorine in ClO2 is +4.
- In Cl2O6, there are six oxygens with an oxidation state of -2 each. The total oxidation state for oxygen is:
\[
6(-2) = -12
\]
Since the compound is neutral, we can use the following equation to find the oxidation state of chlorine:
\[
2x + (-12) = 0 \quad \Rightarrow \quad 2x = 12 \quad \Rightarrow \quad x = +6
\]
Therefore, the oxidation state of chlorine in Cl2O6 is +6.
Step 4: Conclusion
From the above calculations, we can conclude that in Cl2O6, the average oxidation state of chlorine is +6.