Question:

Overfishing reduced food availability for sea lions in California, causing a decline in their population size. In 1972, under the US Endangered Species Act, fishing was banned from sea lion foraging areas. Subsequently, the population of sea lions increased in a logistic form as shown in the figure.The per capita growth rate is highest in the interval ______ and the population growth rate is highest in the interval ____.

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Distinguish \textbf{pathogens} (disease-causing organisms) from \textbf{vectors} (organisms that transmit them). For avian malaria, the pathogen is \emph{Plasmodium}; the mosquito is only the vector.
Updated On: Aug 26, 2025
  • I, II
  • I, III
  • II, II
  • III, II
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The Correct Option is A

Solution and Explanation

Step 1: Recall the logistic-growth model.
Logistic growth is described by \[ \frac{dN}{dt}=rN\!\left(1-\frac{N}{K}\right), \] where \(N\) is population size, \(r\) the intrinsic rate of increase, and \(K\) the carrying capacity.

Step 2: Per-capita growth rate.
Per-capita (per individual) growth is \[ \frac{1}{N}\frac{dN}{dt} \;=\; r\!\left(1-\frac{N}{K}\right). \] This decreases linearly with \(N\) and is maximal when \(N\) is smallest. On the S-shaped curve, the smallest \(N\) is in the early phase (interval I). \(\Rightarrow\) \emph{Per-capita growth rate highest in I.}

Step 3: Total population growth rate.
Total growth \(\frac{dN}{dt}=rN(1-N/K)\) is a quadratic function of \(N\) with a maximum at \(N=K/2\). Graphically this is the steepest part of the logistic curve—its midsection—corresponding to interval II. \(\Rightarrow\) \emph{Population growth rate highest in II.}

Step 4: Conclude.
Per-capita growth: I; total growth: II. Hence option (A) I, II.
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