Question:

Out of $7$ consonants and $4 $ vowels, the number of words (not necessarily meaningful) that can be made, each consisting of $3$ consonants and $2 $ vowels, is

Updated On: Apr 27, 2024
  • 24800
  • 25100
  • 25200
  • 25400
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The Correct Option is C

Solution and Explanation

$3 $ consonants can be selected from 7 consonants$={ }^{7} C_{3} \text { ways }$
$2$ vowels can be selected from 4 vowels
$={ }^{4} C_{2} \text { ways }$
$\therefore$ Required number of words
$={ }^{7} C_{3} \times{ }^{4} C_{2} \times 5 !$
[selected $5$ letters can be arrange in $5 !$, so get, a different words]
$=35 \times 6 \times 120=25200$
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Concepts Used:

Permutations

A permutation is an arrangement of multiple objects in a particular order taken a few or all at a time. The formula for permutation is as follows:

\(^nP_r = \frac{n!}{(n-r)!}\)

 nPr = permutation

 n = total number of objects

 r = number of objects selected

Types of Permutation

  • Permutation of n different things where repeating is not allowed
  • Permutation of n different things where repeating is allowed
  • Permutation of similar kinds or duplicate objects