Question:
Order of energy of orbitals
Order of energy of orbitals
Updated On: May 24, 2024
- 3s>3p>3d>4s
- 3s<3p<3d<4s
- 3s>3p>4s>3d
- 3s<3p<4s<3d
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
The correct option is (D): 3s<3p<4s<3d.
Was this answer helpful?
0
0
Top Questions on The Structure of an Atom
- Using Slater's rule, the shielding constant and effective nuclear charge for the outermost electron of Mg are respectively.
- CUET (PG) - 2023
- Chemistry
- The Structure of an Atom
- A state (n1, n2 ) for a particle in a rectangular box with sides of length L1 = L and L2 = 2L that is accidentally degenerate with the state (4, 4) is
- CUET (PG) - 2023
- Chemistry
- The Structure of an Atom
- To generate molecular orbitals in molecules consisting of three or more atoms, which of the following is correct
- CUET (PG) - 2023
- Chemistry
- The Structure of an Atom
- The experimental magnetic moment (3.4 BM) of a hydrated salt of \(Eu^{3+}\) at 300 K is significantly different from calculated value. The difference is due to (Given atomic number of \(E_u\) = 63)
- CUET (PG) - 2023
- Chemistry
- The Structure of an Atom
- Consider the following pair of electrons :
1. \(n=3, l=1, m_l =1, m_s = + \frac{1}{2}\; and \;n = 3, l=2, m_l =1, m_s=+\frac{1}{2}\)
2. \(n=3,l=2,m_l=-2,m_s=-\frac{1}{2}\;and n=3,l=2,m_l=-1,m_s=-\frac{1}{2}\)
3. \(n=3,l=2,m_l=2,m_s=+\frac{1}{2}\;and \;n=4,l=2,m_l=2,m_s=+\frac{1}{2}\)- CUET (PG) - 2023
- Verbal Reasoning
- The Structure of an Atom
View More Questions
Questions Asked in TS POLYCET exam
- The value of \(\tan 26^\circ. \tan 64^\circ\) is
- TS POLYCET - 2023
- Trigonometry
- When white light is incident on a glass prism, the least deviated colour is
- TS POLYCET - 2023
- Wave Optics
- If 5x+py+8=0 and 10x+15y+12=0 has no solution, then p =
- TS POLYCET - 2023
- Quadratic Equations
- If \(\sec \theta = \frac{2}{\sqrt{3}}\),then \(cosθ=\)
- TS POLYCET - 2023
- Trigonometry
- In the figure, if AP and AQ are the two tangents to a circle with centre 'O' so that \(∠OQP=15°\), then \(∠QAP=\)
- TS POLYCET - 2023
- Tangent to a Circle
View More Questions