Question:
One of the vertices of the major axis of an ellipse is (1, 1) and one of the vertices of its minor axis is (-2, -1). If the centre of the ellipse is (-2, 1), then the equation of the ellipse is
One of the vertices of the major axis of an ellipse is (1, 1) and one of the vertices of its minor axis is (-2, -1). If the centre of the ellipse is (-2, 1), then the equation of the ellipse is
Updated On: Jun 10, 2024
- \(\frac{(x+2)^2}{9}+\frac{(y-1)^2}{4}=1\)
- \(\frac{(x+2)^2}{16}+\frac{(y-1)^2}{4}=1\)
- \(\frac{(x-2)^2}{9}+\frac{(y+1)^2}{4}=1\)
- \(\frac{(x-2)^2}{16}+\frac{(y+1)^2}{4}=1\)
- \(\frac{(x+2)^2}{9}+\frac{(y-1)^2}{2}=1\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{(x+2)^2}{9}+\frac{(y-1)^2}{4}=1\)
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