One mole of \( A (g) \) is heated to \( T(K) \) till the following equilibrium is obtained
\[
A(g) \rightleftharpoons B(g)
\]
The equilibrium constant of this reaction is \( 10^{-1} \). After reaching the equilibrium, 0.5 moles of A (g) is added and heated. The equilibrium is again established. The value of \( \left[\frac{A}{B}\right] \) is
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- \( 10^{-1} \)
- \( 10^{2} \)
- 1
- 100
The Correct Option is B
Solution and Explanation
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