On the basis of the given data, estimate the value of National Income (NNPFC):
| S.No. | Items | Amount (in ₹ Crore) |
| (i) | Household Consumption Expenditure | 1,800 |
| (ii) | Gross Business Fixed Capital Formation | 1,150 |
| (iii) | Gross Residential Construction Expenditure | 1,020 |
| (iv) | Government Final Consumption Expenditure | 2,170 |
| (v) | Excess of Imports over Exports | 720 |
| (vi) | Inventory Investments | 540 |
| (vii) | Gross Public Investments | 1,300 |
| (viii) | Net Indirect Taxes | 240 |
| (ix) | Net Factor Income from Abroad | (-) 250 |
| (x) | Consumption of Fixed Capital | 440 |
National Income (NNPFC) is calculated by subtracting the depreciation (Consumption of Fixed Capital) from the Gross National Product (GNP).
First, let's calculate the Gross National Product (GNP) at factor cost: \[ \text{GNP} = C + I + G + (X - M) + \text{Net Factor Income from Abroad} \] Where: - \(C\) is the Household Consumption Expenditure = ₹1,800 crore
- \(I\) is the Gross Business Fixed Capital Formation + Gross Residential Construction Expenditure + Inventory Investments + Gross Public Investments = ₹1,150 + ₹1,020 + ₹540 + ₹1,300 = ₹4,010 crore
- \(G\) is the Government Final Consumption Expenditure = ₹2,170 crore
- \((X - M)\) is the Excess of Imports over Exports = ₹720 crore
- Net Factor Income from Abroad = ₹-250 crore
Substituting these values into the GNP equation: \[ \text{GNP} = 1,800 + 4,010 + 2,170 + 720 + (-250) = 8,450 \text{ crore} \] Now, to calculate National Income (NNPFC), we subtract the consumption of fixed capital (depreciation): NNPFC = GNP - Consumption of Fixed Capital
NNPFC = 8,450 - 440 = 8,010 crore
Thus, the value of National Income (NNPFC) is ₹8,010 crore.
On the basis of the following hypothetical data, calculate the percentage change in Real Gross Domestic Product (GDP) in the year 2022 – 23, using 2020 – 21 as the base year.
| Year | Nominal GDP | Nominal GDP (Adjusted to Base Year Price) |
| 2020–21 | 3,000 | 5,000 |
| 2022–23 | 4,000 | 6,000 |
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
Study the given molecular structure of double-stranded polynucleotide chain of DNA and answer the questions that follow. 
(a) How many phosphodiester bonds are present in the given double-stranded polynucleotide chain?
(b) How many base pairs are there in each helical turn of double helix structure of DNA? Also write the distance between a base pair in a helix.
(c) In addition to H-bonds, what confers additional stability to the helical structure of DNA?
