Analysis of Proton's Path in a Non-uniform Magnetic Field
Given:
- A proton moves with velocity \( \vec{V} \) in a plane (paper plane)
- The trajectory is curved, suggesting a non-uniform magnetic field \( \vec{B} \)
- We are to determine the direction and relative magnitude of \( \vec{B} \) at points P, Q, and R.
Key Concepts:
- The magnetic force on a moving charge is given by: \[ \vec{F} = q (\vec{V} \times \vec{B}) \]
- For circular/curved motion: \[ \text{Centripetal force} = \frac{mv^2}{r} = qvB \Rightarrow r = \frac{mv}{qB} \] Thus, a smaller radius indicates a stronger magnetic field.
- Direction of magnetic field can be determined using the right-hand rule: - Fingers in direction of \( \vec{V} \) - Curl toward \( \vec{F} \) (curvature) - Thumb gives \( \vec{B} \)
Answer:
➡ Direction of Magnetic Field:
Since the path of the proton (positive charge) curves to the left, the magnetic force is directed toward the center of curvature. Using the right-hand rule with velocity tangents, we find:
- At all points P, Q, R, the magnetic field is perpendicular to the plane and directed into the page (denoted by a cross “×”).
➡ Relative Magnitude of Magnetic Field:
Since: \[ r = \frac{mv}{qB} \Rightarrow B \propto \frac{1}{r} \] The smaller the radius of curvature, the stronger the magnetic field.
Looking at the image:
- At point Q: radius is smallest ⇒ \( B_Q \) is the strongest.
- At point R: intermediate radius ⇒ \( B_R \) is moderate.
- At point P: largest radius ⇒ \( B_P \) is the weakest.
✔ Final Answer:
- Direction of \( \vec{B} \) at P, Q, R: Into the page
- Relative magnitudes: \( B_Q > B_R > B_P \)