Let the cost price of a pen be \( x \) and that of a book be \( y \).
The first condition is: \[ 0.95x + 1.15y = x + y + 7 \tag{1} \]
The second condition is: \[ 1.05x + 1.10y = x + y + 13 \tag{2} \]
Rearranging Equation (1): \[ 0.95x + 1.15y - x - y = 7 \\ -0.05x + 0.15y = 7 \tag{3} \]
Rearranging Equation (2): \[ 1.05x + 1.10y - x - y = 13 \\ 0.05x + 0.10y = 13 \tag{4} \]
Now add equations (3) and (4): \[ (-0.05x + 0.15y) + (0.05x + 0.10y) = 7 + 13 \\ 0.25y = 20 \Rightarrow y = 80 \]
The cost price of the book is ₹80.
When $10^{100}$ is divided by 7, the remainder is ?