Let’s analyze both statements one by one.
(A) OF is paramagnetic while F\(_2\) is diamagnetic: - OF (oxygen fluoride, OF) has an unpaired electron in its molecular orbitals, making it paramagnetic. - F\(_2\) (fluorine molecule), on the other hand, has all of its electrons paired, making it diamagnetic. So, this statement is correct.
(B) OF is more stable towards dissociation into atoms: - OF is more stable than F\(_2\) in terms of dissociation. F\(_2\) has a relatively weak bond compared to OF, making OF less likely to dissociate into atoms. So, this statement is also correct.
Since both statements (A) and (B) are correct, the correct answer is \( \boxed{{C}} \).
Match List I with List II.
In which of the following reactions of H$_2$O$_2$ acts as an oxidizing agent (either in acidic, alkaline, or neutral medium)?
% Given Reactions
(i) \( 2Fe^{2+} + H_2O_2 \rightarrow \)
(ii) \( 2MnO_4^- + 6H^+ + 5H_2O_2 \rightarrow \)
(iii) \( I_2 + H_2O_2 + 2OH^- \rightarrow \)
(iv) \( Mn^{2+} + H_2O_2 \rightarrow \)