Both Y and B are dehydrated with Conc. H\(_2\)SO\(_4\)/443 K
Both Y and B are dehydrated with 20% H\(_3\)PO\(_4\)/358 K
Y is dehydrated with Conc. H\(_2\)SO\(_4\)/443 K and B with 20% H\(_3\)PO\(_4\)/358 K
B is dehydrated with Conc. H\(_2\)SO\(_4\)/443 K and Y with 20% H\(_3\)PO\(_4\)/358 K
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The Correct Option isD
Solution and Explanation
1. Reaction of C\(_3\)H\(_4\) with Hg\(^{2+}\)/H\(_2\)O:
C\(_3\)H\(_4\) is propyne (CH\(\equiv\)C-CH\(_3\)).
Hydration of alkynes in the presence of Hg\(^{2+}\)/H\(_2\)O leads to the formation of a ketone.
X is propanone (CH\(_3\)COCH\(_3\)).
2. Reaction of propanone with MeMgBr followed by H\(_2\)O:
Propanone reacts with methyl magnesium bromide (MeMgBr) to form a tertiary alcohol.
Y is 2-methylpropan-2-ol ((CH\(_3\))\(_3\)COH).
3. Reaction of C\(_3\)H\(_6\) with (BH\(_3\))\(_2\) followed by H\(_2\)O\(_2\)/OH\(^{-}\):
C\(_3\)H\(_6\) is propene (CH\(_3\)CH=CH\(_2\)).
Hydroboration-oxidation of alkenes leads to the formation of an alcohol.
B is propan-1-ol (CH\(_3\)CH\(_2\)CH\(_2\)OH).
4. Dehydration of alcohols:
Tertiary alcohols (Y) are easily dehydrated with mild conditions like 20% H\(_3\)PO\(_4\)/358 K.
Primary alcohols (B) require stronger conditions like Conc. H\(_2\)SO\(_4\)/443 K for dehydration.
Therefore, B is dehydrated with Conc. H\(_2\)SO\(_4\)/443 K and Y with 20% H\(_3\)PO\(_4\)/358 K.
Final Answer:
B is dehydrated with Conc. H\(_2\)SO\(_4\)/443 K and Y with 20% H\(_3\)PO\(_4\)/358 K.
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