Observe the following reactions (unbalanced): $ P_2O_3 + H_2O \rightarrow X $ $ P_4O_{10} + H_2O \rightarrow Y $ The number of $ P=O $ bonds present in $ X, Y $ are respectively:

Question

Observe the following reactions (unbalanced):   $ P_2O_3 + H_2O \rightarrow X $ $ P_4O_{10} + H_2O \rightarrow Y $ The number of $ P=O $ bonds present in $ X, Y $ are respectively:

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Step 1: Understanding the Hydrolysis of Phosphorus Oxides   - $ P_2O_3 $ (Phosphorus(III) oxide) reacts with water to form phosphorous acid ($ H_3PO_3 $): $$ P_2O_3 + 3H_2O \rightarrow 2H_3PO_3 $$ - In $ H_3PO_3 $, there is one $ P=O $ bond . - $ P_4O_{10} $ (Phosphorus(V) oxide) reacts with water to form phosphoric acid ($ H_3PO_4 $): $$ P_4O_{10} + 6H_2O \rightarrow 4H_3PO_4 $$ - In $ H_3PO_4 $, there is also one $ P=O $ bond per molecule .  Step 2: Evaluating the Given Options   - Option (1): Incorrect, as $ X = H_3PO_3 $ has 1 $ P=O $ bond, and $ Y = H_3PO_4 $ also has 1 $ P=O $ bond. - Option (2): Incorrect, as $ Y $ does not have 2 $ P=O $ bonds. - Option (3): Incorrect, as $ X $ does not have 2 $ P=O $ bonds. - Option (4): Correct, as both $ X $ and $ Y $ have 1 $ P=O $ bond each. Thus, the correct answer is  Option (4) .

Answer

Answer

Answer

Answer

<div>$ 1, 1 $

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Observe the following reactions (unbalanced):

\( P_2O_3 + H_2O \rightarrow X \)

\( P_4O_{10} + H_2O \rightarrow Y \)

The number of \( P=O \) bonds present in \( X, Y \) are respectively:

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The Correct Option is D

Solution and Explanation

Top Questions on Classical Idea Of Redox Reactions – Oxidation And Reduction Reactions

Questions Asked in TS EAMCET exam

Observe the following reactions (unbalanced): \( P_2O_3 + H_2O \rightarrow X \) \( P_4O_{10} + H_2O \rightarrow Y \) The number of \( P=O \) bonds present in \( X, Y \) are respectively: