Observe the following reactions: $$ \text{I. } H_2O(l) + 2Na(s) \rightarrow 2NaOH(aq) + H_2(g) $$ $$ \text{II. } 2H_2O(l) + 2F_2(g) \rightarrow 4H^+(aq) + 4F^-(aq) + O_2(g) $$ Identify the correct statement:

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To identify the correct statement about the reactions, we need to analyze the oxidation and reduction processes in each reaction. Reaction I: $$ H_2O(l) + 2Na(s) \rightarrow 2NaOH(aq) + H_2(g) $$ Oxidation: Sodium ($Na$) is oxidized from $0$ to $+1$. Reduction: Water ($H_2O$) is reduced. The hydrogen in $H_2O$ goes from $+1$ to $0$ in $H_2$. Thus, in Reaction I, water is reduced. Reaction II: $$ 2H_2O(l) + 2F_2(g) \rightarrow 4H^+(aq) + 4F^-(aq) + O_2(g) $$ Oxidation: Water ($H_2O$) is oxidized. The oxygen in $H_2O$ goes from $-2$ to $0$ in $O_2$. Reduction: Fluorine ($F_2$) is reduced from $0$ to $-1$. Thus, in Reaction II, water is oxidized. Correct Statement: In Reaction I, water is reduced. In Reaction II, water is oxidized. The correct option is: $$ \boxed{\text{(3) In reaction I water is reduced and in reaction II water is oxidized.}} $$

Answer

In both reaction I and reaction II, water is oxidized.

Answer

In both reaction I and reaction II, water is reduced.

Answer

In reaction I water is reduced and in reaction II water is oxidized.

Answer

In reaction I water is oxidized and in reaction II water is reduced.

Observe the following reactions: \[ \text{I. } H_2O(l) + 2Na(s) \rightarrow 2NaOH(aq) + H_2(g) \] \[ \text{II. } 2H_2O(l) + 2F_2(g) \rightarrow 4H^+(aq) + 4F^-(aq) + O_2(g) \] Identify the correct statement:

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The Correct Option is C

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