Methyl but-1-ene has the structure \( \text{CH}_3-\text{CH}_2-\text{C}=\text{CH}_2 \), where:
- The single bonds are sigma bonds,
- The double bonds consist of one sigma bond and one pi bond.
1. Step 1: Count the sigma bonds:
- Each single bond in the molecule is a sigma bond. The structure consists of 10 single bonds:
- 3 C-H bonds in the methyl group (\( \text{CH}_3 \)),
- 2 C-H bonds in the ethyl group (\( \text{CH}_2 \)),
- 4 C-C single bonds (2 in the backbone of the molecule and 1 between \( \text{C}_2 \) and \( \text{C}_3 \)),
- 1 C-H bond at the end of the molecule (for the \( \text{CH}_2 \) group).
So, the total number of sigma bonds is 10.
2. Step 2: Count the pi bonds:
The double bond between \( \text{C}_3 \) and \( \text{C}_4 \) consists of 1 sigma bond and 1 pi bond.
Thus, the molecule contains 10 sigma bonds and 3 pi bonds.