Question:
nth term of the series
\(1+\frac{3}{7}+\frac{5}{7^2}+\frac{1}{7^2}+...\) is
nth term of the series
\(1+\frac{3}{7}+\frac{5}{7^2}+\frac{1}{7^2}+...\) is
\(1+\frac{3}{7}+\frac{5}{7^2}+\frac{1}{7^2}+...\) is
Updated On: Dec 5, 2024
- \(\frac{2n-1}{7^n}\)
- \(\frac{2n-1}{7^{n-1}}\)
- \(\frac{2n+1}{7^{n-1}}\)
- \(\frac{2n+1}{7^n}\)
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The Correct Option is B
Solution and Explanation
The correct answer is (V) :\(\frac{2n-1}{7^{n-1}}\) .
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