In the first step, bromine reacts with nitrobenzene in the presence of FeBr₃, forming a bromonitrobenzene derivative (product ).
In the second step, sodium nitrite () at 273 K reacts with the product to form a diazonium salt ().
In the third step, the diazonium salt reacts with dilute HCl to produce a phenol derivative.
Finally, when the reaction mixture is warmed with water, the diazonium group is replaced by a hydroxyl group, forming as the final product, which corresponds to option (C).
Thus, the final product is .
(b.)Calculate the potential for half-cell containing 0.01 M KCrO(aq), 0.01 M Cr(aq), and 1.0 x 10 M H(aq).