Name the gases collected at the anode and cathode.
Solution and Explanation
During the electrolysis of water, an electric current is passed through acidified water to decompose it into its constituent gases.
Step 2: Reactions at the electrodes:
- At the cathode (negative electrode), reduction takes place:
\[ 2H^+ + 2e^- \rightarrow H_2 \]
- So, hydrogen gas (H₂) is collected at the cathode.
- At the anode (positive electrode), oxidation takes place:
\[ 2H_2O \rightarrow O_2 + 4H^+ + 4e^- \]
- So, oxygen gas (O₂) is collected at the anode.
Step 3: Conclusion:
- Gas at the cathode: Hydrogen (H₂)
- Gas at the anode: Oxygen (O₂)
Top Questions on Electrolysis
A solution of aluminium chloride is electrolyzed for 30 minutes using a current of 2A. The amount of the aluminium deposited at the cathode is _________
- JEE Main - 2025
- Chemistry
- Electrolysis
Electrolysis of 600 mL aqueous solution of NaCl for 5 min changes the pH of the solution to 12. The current in Amperes used for the given electrolysis is ….. (Nearest integer).
- JEE Main - 2025
- Chemistry
- Electrolysis
- In electrolysis of dilute H\(_2\)SO\(_4\), what is liberated at anode?
- BCECE - 2025
- Chemistry
- Electrolysis
If \( E^\circ_{Fe^{2+}/Fe} = -0.441 \, \text{V} \) and \( E^\circ_{Fe^{3+}/Fe^{2+}} = 0.771 \, \text{V} \),
the standard emf of the cell reaction \( Fe(s) + 2Fe^{3+}(aq) \rightarrow 3Fe^{2+}(aq) \) is:\[ E^\circ_{\text{cell}} = E^\circ_{\text{cathode}} - E^\circ_{\text{anode}} \] For the reaction, \( Fe^{3+} \) is reduced to \( Fe^{2+} \) (reduction at the cathode), and \( Fe \) is oxidized to \( Fe^{2+} \) (oxidation at the anode). So: \[ E^\circ_{\text{cell}} = E^\circ_{Fe^{3+}/Fe^{2+}} - E^\circ_{Fe^{2+}/Fe} \] \[ E^\circ_{\text{cell}} = 0.771 \, \text{V} - (-0.441 \, \text{V}) = 0.771 + 0.441 = 1.212 \, \text{V} \] Hence, the standard emf of the cell reaction is \( 1.212 \, \text{V} \).
- AP EAPCET - 2025
- Chemistry
- Electrolysis
Consider the following
Statement-I: Kolbe's electrolysis of sodium propionate gives n-hexane as product.
Statement-II: In Kolbe's process, CO$_2$ is liberated at anode and H$_2$ is liberated at cathode.- AP EAPCET - 2025
- Chemistry
- Electrolysis
Questions Asked in CBSE X exam
- To get an image of magnification -1 on a screen using a lens of focal length 20 cm, the object distance must be:
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.
- CBSE Class X - 2025
- Geometry
सड़क सुरक्षा के प्रति जागरूकता हेतु ट्रैफिक पुलिस की ओर से जनहित में जारी एक आकर्षक विज्ञापन लगभग 100 शब्दों में तैयार कीजिए।
- CBSE Class X - 2025
- पत्र लेखन
- Suggest any two measures to ensure participation of women in public life.
- CBSE Class X - 2025
- Gender, Religion and Caste
The following data shows the number of family members living in different bungalows of a locality:
Number of Members 0−2 2−4 4−6 6−8 8−10 Total Number of Bungalows 10 p 60 q 5 120
If the median number of members is found to be 5, find the values of p and q.- CBSE Class X - 2025
- Median of Grouped Data