List-I (Species) | List-II (Maximum allowed concentration in ppm in drinking water) | ||
A | F- | I | < 50 ppm |
B | \(SO^{2-}_4\) | II | < 5 ppm |
C | \(NO^-_3\) | III | < 2 ppm |
D | Zn | IV | < 500 ppm |
Choose the correct answer from the options given below :
A. F$^-$ (Fluoride): The allowed concentration is less than 1.5 ppm, but for safe drinking water, it is set at $<$ 50 ppm.
B. SO$_4^{2-}$ (Sulfates): Allowed concentration is up to $<$ 500 ppm to prevent taste or odor changes in water.
C. NO$_3$ (Nitrates): The maximum safe limit is $<$ 2 ppm to avoid health effects like methemoglobinemia.
D. Zn (Zinc): Safe concentration is $<$ 500 ppm to maintain taste quality and health safety.
Thus, the correct matching is A-I, B-II, C-III, D-IV.
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 gof water, it depresses the freezing point by 0.2°C. The percentage association of solute A in water is :
[Given : Molar mass of A = 93 g mol–1. Molal depression constant of water is 1.86 K kg mol–1.]
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: