| List-I (Species) | List-II (Maximum allowed concentration in ppm in drinking water) | ||
| A | F- | I | < 50 ppm |
| B | \(SO^{2-}_4\) | II | < 5 ppm |
| C | \(NO^-_3\) | III | < 2 ppm |
| D | Zn | IV | < 500 ppm |
Choose the correct answer from the options given below :
A. F$^-$ (Fluoride): The allowed concentration is less than 1.5 ppm, but for safe drinking water, it is set at $<$ 50 ppm.
B. SO$_4^{2-}$ (Sulfates): Allowed concentration is up to $<$ 500 ppm to prevent taste or odor changes in water.
C. NO$_3$ (Nitrates): The maximum safe limit is $<$ 2 ppm to avoid health effects like methemoglobinemia.
D. Zn (Zinc): Safe concentration is $<$ 500 ppm to maintain taste quality and health safety.
Thus, the correct matching is A-I, B-II, C-III, D-IV.
Solute A associates in water. When 0.7 g of solute A is dissolved in 42.0 gof water, it depresses the freezing point by 0.2°C. The percentage association of solute A in water is :
[Given : Molar mass of A = 93 g mol–1. Molal depression constant of water is 1.86 K kg mol–1.]
For the AC circuit shown in the figure, $ R = 100 \, \text{k}\Omega $ and $ C = 100 \, \text{pF} $, and the phase difference between $ V_{\text{in}} $ and $ (V_B - V_A) $ is 90°. The input signal frequency is $ 10^x $ rad/sec, where $ x $ is:
Two parabolas have the same focus $(4, 3)$ and their directrices are the $x$-axis and the $y$-axis, respectively. If these parabolas intersect at the points $A$ and $B$, then $(AB)^2$ is equal to:
A point particle of charge \( Q \) is located at \( P \) along the axis of an electric dipole 1 at a distance \( r \) as shown in the figure. The point \( P \) is also on the equatorial plane of a second electric dipole 2 at a distance \( r \). The dipoles are made of opposite charge \( q \) separated by a distance \( 2a \). For the charge particle at \( P \) not to experience any net force, which of the following correctly describes the situation?
