Question

Mrs Ranga has three children and has difficulty remembering their ages and months of their birth. The clue below may help her remember.
- The boy, who was born in June, is 7 years old.
- One of the children is 4 years old but it was not Anshuman.
- Vaibhav is older than Suprita.
- One of the children was born in September, but it was not Vaibhav.
- Suprita’s birthday is in April.
- The youngest child is only 2 years old.
Based on the above clues, which statement is true?

• A. Vaibhav is the oldest, followed by Anshuman (born in September), youngest is Suprita (born in April)
• B. Anshuman is the oldest (born in June), followed by Suprita (4-year-old), youngest is Vaibhav (2-year-old)
• C. Vaibhav is the oldest (7-year-old, born in April), followed by Suprita, youngest is Anshuman (born in September)
• D. Suprita is the oldest (born in April), followed by Vaibhav (born in June), youngest is Anshuman (born in September)

Hint:

Assign fixed data first (birth month/age), then apply inequalities to resolve identities.

Answer 1

The Correct Option is B

From clues: - 7-year-old born in June ⇒ Oldest child is born in June. Not Anshuman as 4-year-old is not him. ⇒ Anshuman not 4 ⇒ He must be 7 or 2.
- Suprita’s birthday = April ⇒ She is not 7 (oldest born in June), not 2 (youngest is 2), so she is 4 years old.
- Vaibhav older than Suprita ⇒ Vaibhav is not 2, must be 7 or 4. But 4-year-old already Suprita ⇒ Vaibhav is 2-year-old? No, contradiction ⇒ So Anshuman = 7-year-old (born in June), Suprita = 4-year-old (April), Vaibhav = 2-year-old (September).