Question

In the cursed land of Weirdisthan, strength of animals was disproportionately distributed. Horse has half the strength of a Dog and four times the strength of an Elephant. Monkey has three times the strength of a Rhino. Elephant has half the strength of a Rhino. One Dog was becoming a danger for other animals and they decided to assign a team of animal soldiers to overpower him. Which team of soldiers managed to overpower the dog?

• A. One Rhino and One Monkey
• B. One Rhino, One Horse and One Elephant
• C. One Horse and One Monkey
• D. Two Horses

Hint:

In logic puzzles with multiple relative statements, the easiest way to solve is to assign a base value (usually 1) to one of the items and then calculate the values of all other items relative to it.

Answer 1

The Correct Option is C

Step 1: Understanding the Question:
This is a logic puzzle where we need to determine the relative strengths of several animals based on a set of given relationships and then find a team whose combined strength is greater than that of a Dog.
Step 2: Establish Relative Strengths:
Let's denote the strength of each animal by its first letter: H, D, E, M, R. We are given:
\( H = \frac{1}{2} D \)
\( H = 4E \)
\( M = 3R \)
\( E = \frac{1}{2} R \) Let's assign a base strength value to one animal and calculate the others. Let the strength of an Elephant (E) be 1 unit.
If \( E = 1 \), then from \( E = \frac{1}{2} R \), we get \( R = 2E = 2 \).
Now that we have R, from \( M = 3R \), we get \( M = 3 \times 2 = 6 \).
From \( H = 4E \), we get \( H = 4 \times 1 = 4 \).
Finally, from \( H = \frac{1}{2} D \), we get \( D = 2H = 2 \times 4 = 8 \). So, the relative strengths are: Dog=8, Monkey=6, Horse=4, Rhino=2, Elephant=1.
Step 3: Evaluate the Teams:
The goal is to find a team whose total strength is greater than the Dog's strength (i.e.,>8).
- Team A: One Rhino + One Monkey = R + M = 2 + 6 = 8. (Strength is equal to the Dog, not enough to overpower).
- Team B: One Rhino + One Horse + One Elephant = R + H + E = 2 + 4 + 1 = 7. (Strength is less than the Dog).
- Team C: One Horse + One Monkey = H + M = 4 + 6 = 10. (Strength is greater than the Dog).
- Team D: Two Horses = H + H = 4 + 4 = 8. (Strength is equal to the Dog).
Step 4: Final Answer:
Only the team of One Horse and One Monkey has a combined strength of 10, which is greater than the Dog's strength of 8. Therefore, they can overpower the dog. This corresponds to option (C).