Question

Moment of Inertia (M.I.) of four bodies having same mass ‘M‘ and radius ‘2R‘ are as follows:

I₁ = M.I. of solid sphere about its diameter

I₂ = M.I. of solid cylinder about its axis

I₃ = M.I. of solid circular disc about its diameter.

I₄ = M.I. of thin circular ring about its diameter

If 2(I₂ + I₃) + I₄ = x⋅ I₁ then the value of x will be ______.

Answer 1

Correct Answer: 5

\(2(\frac{1}{2}+\frac{1}{2})×M(2R)^2+\frac{1}{2}M(2R)^2=x\frac{2}{5}M(2R)^2\)

\(⇒1+\frac{1}{2}+\frac{1}{2}=x×\frac{2}{5}\)

⇒ x = 5