Tominimize\(Z=3x+9y\),plottheconstraintsonagraphandfindthefeasibleregion:
1.\(x+3y\leq60\)isalinewithinterceptsat\(x=60,y=20\).
2.\(x+y\geq10\)isalinepassingthrough\((10,0)\)and\((0,10)\).
3.\(x\leqy\)representstheregionbelow\(x=y\).
4.\(x\geq0,y\geq0\)restrictstothefirstquadrant.
Thefeasibleregionisbounded,and\(Z=3x+9y\)isevaluatedatcornerpoints.Solvefor\(Z\)atthesevertices:
\begin{itemize}
\item\((0,10)\):\(Z=3(0)+9(10)=90\),
\item\((0,20)\):\(Z=3(0)+9(20)=180\),
\item\((30,10)\):\(Z=3(30)+9(10)=90+30=120\).
\end{itemize}
Theminimumvalueis\(Z=90\)at\((0,10)\).