Let the number of \(O^{–2}\) ions be \(100\)
and the number of \(Fe^{+2}\) ions be \(X\)
The number of \(Fe^{+3}\) ions be \((93 – X)\)
\(∴ X(2) + (93 – X)3 = 200\)
\(279 – X = 200\)
\(X = 279-200\)
\(X = 79\)
∴ % of \(Fe^{+2}\) ions\(=\frac {79}{93}×100\)
≃ 85%
So, the answer is 85%.
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Read More: Some Basic Concepts of Chemistry
There are two ways of classifying the matter:
Matter can exist in three physical states:
Based upon the composition, matter can be divided into two main types: