Match the LIST-I with LIST-II:

Choose the correct answer from the options given below :
To solve this matching problem, we need to correctly associate each category of molecules (LIST-I) with the appropriate example (LIST-II) based on the octet rule. Let's break down each pair:
Based on the reasoning above, the correct matching is:
A-IV, B-II, C-I, D-III
(A) Molecules obeying octet rule: Molecules like CO2 and CCl4 obey the octet rule, where each atom completes its octet. Hence, A corresponds to IV.
(B) Molecules with incomplete octet: Molecules such as BCl3 and AlCl3 have an incomplete octet on the central atom. Hence, B corresponds to II.
(C) Molecules with incomplete octet with odd electron: NO and NO2 have an odd number of electrons and an incomplete octet. Hence, C corresponds to I.
(D) Molecules with expanded octet: Molecules like H2SO4 and PCl5 have an expanded octet, which means the central atoms have more than eight electrons. Hence, D corresponds to III.
Thus, the correct matching is A-IV, B-II, C-I, D-III.
From the given following (A to D) cyclic structures, those which will not react with Tollen's reagent are : 
Compound 'P' undergoes the following sequence of reactions : (i) NH₃ (ii) $\Delta$ $\rightarrow$ Q (i) KOH, Br₂ (ii) CHCl₃, KOH (alc), $\Delta$ $\rightarrow$ NC-CH₃. 'P' is : 

Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.