Step 1: Recall Helmholtz function.
\[
a = u - Ts
\]
But in given table, $u - Ts$ corresponds to Gibbs? Actually, by definition:
- Helmholtz free energy: $a = u - Ts$ $\Rightarrow$ matches B2.
- Gibbs free energy: $g = h - Ts$ $\Rightarrow$ matches B4.
Step 2: Recall $Tds$ equation.
From first law:
\[
du = Tds - Pdv
\]
Thus A3 $\to$ B3.
Step 3: Clapeyron–Clausius relation.
\[
\left(\frac{d}{dT} \ln P \right)_{sat} = \frac{h_{fg}}{RT^2}
\]
So A4 $\to$ B1.
Step 4: Matching summary.
- A1 $\to$ B2
- A2 $\to$ B4
- A3 $\to$ B3
- A4 $\to$ B1
Final Answer:
\[
\boxed{\text{Option (D)}}
\]