Question:

The following data is given for a ternary \(ABC\) gas mixture at 12 MPa and 308 K:

\(y_i\): mole fraction of component \(i\) in the gas mixture
\(\hat{\phi}_i\): fugacity coefficient of component \(i\) in the gas mixture at 12 MPa and 308 K
The fugacity of the gas mixture is _________ MPa (rounded off to 3 decimal places).

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When calculating the fugacity of a gas mixture, it's important to consider the contribution of each component's fugacity, which depends on its mole fraction, fugacity coefficient, and the system pressure.
Updated On: Apr 11, 2025
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Solution and Explanation

Step 1: Calculate the fugacity of each component. For Component \(A\): \(f_A = 0.55 \times 0.75 \times 12 = 4.95 \, {MPa}\) For Component \(B\): \(f_B = 0.20 \times 0.80 \times 12 = 1.92 \, {MPa}\) For Component \(C\): \(f_C = 0.25 \times 0.95 \times 12 = 2.85 \, {MPa}\) 
Step 2: Sum the fugacities of all components to find the total fugacity of the mixture. \[ f = f_A + f_B + f_C = 4.95 + 1.92 + 2.85 = 9.72 \, {MPa}\]

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