Question

Match the following reactions with their corresponding products: \begin{center} \includegraphics[width=1\textwidth]{TSE 158.png} \end{center}

• A.
• B.
• C.
• D.

Hint:

When dealing with aromatic compounds, pay attention to the reagents and their oxidation or reduction properties to predict the product.

Answer 1

The Correct Option is A

The reactions listed in the question involve different reagents and conditions, each causing specific transformations in the aromatic compounds. Here is the step-by-step breakdown of the transformations: 1. A (Phenol + Zn): - The reaction of phenol with zinc (\(Zn\)) at elevated temperatures typically leads to the reduction of the hydroxyl group (\(-OH\)) and the formation of benzene. - Hence, A corresponds to Benzene (II). 2. B (Phenol with Na\(_2\)Cr\(_2\)O\(_7\)/H\(_2\)SO\(_4\)): - This reaction is an oxidation reaction where phenol undergoes oxidation by chromic acid (\(Na_2Cr_2O_7\)/\(H_2SO_4\)), forming Benzquinone (I) as a product. 3. C (Phenol with CHCl\(_3\)/NaOH, followed by H\(^+\)): - The reaction of phenol with chloroform (\(CHCl_3\)) and sodium hydroxide (\(NaOH\)) followed by acidification leads to the formation of Salicylaldehyde (IV), which is an aldehyde derivative of phenol. 4. D (Phenol with NaOH, followed by \((ii) CO_2\) under H\(^+\)): - This reaction involves the formation of Salicylic acid (III) through a Kolbe-Schmitt reaction, where phenol is first treated with sodium hydroxide and then carbon dioxide is added under acidic conditions to produce the carboxylated derivative. Thus, the correct matching is: - A - II (Benzene from phenol + Zn) - B - I (Benzquinone from phenol with Na\(_2\)Cr\(_2\)O\(_7\)) - C - IV (Salicylaldehyde from phenol with CHCl\(_3\)/NaOH) - D - III (Salicylic acid from phenol with NaOH and CO\(_2\)) \vspace{0.5cm}