Question

Match the following: \[ \begin{array}{|c|c|} \hline \textbf{Molecule / Ion} & \textbf{Shape} \\ \hline \text{A. } \text{I}_3^- & 1. \text{T-shaped} \\ \text{B. } \text{ClF}_3 & 2. \text{See-Saw} \\ \text{C. } \text{H}_2\text{O} & 3. \text{Angular} \\ \text{D. } \text{SF}_4 & 4. \text{Linear} \\ \hline \end{array} \]

• A. A-4, B-1. C-3, D-2
• B. A-4, B-1, C-2, D-3
• C. A-2, B-3, C-4, D-1
• D. A-3, B-2, C-4, D-1

Hint:

In VSEPR theory, the shape of the molecule depends on the number of bonding pairs and lone pairs around the central atom.

Answer 1

The Correct Option is A

- Molecule A (\(\text{I}_3\)): T-shaped, as it follows the structure of a tri-atomic molecule with three bonding pairs and two lone pairs.
- Molecule B (\(\text{ClF}_3\)): T-shaped due to the presence of three bonding pairs and two lone pairs on the central atom.
- Molecule C (\(\text{H}_2\text{O}\)): Angular shape, due to two bonding pairs and two lone pairs on oxygen.
- Molecule D (\(\text{SF}_4\)): See-saw shape, with four bonding pairs and one lone pair on sulfur.