Question

Match List I with List II

LIST I		LIST II
A	Isothermal Process	I	Work done by the gas decreases internal energy
B	Adiabatic Process	II	No change in internal energy
C	Isochoric Process	III	The heat absorbed goes partly to increase internal energy and partly to do work
D	Isobaric Process	IV	No work is done on or by the gas

Choose the correct answer from the options given below:

• A. A-I, B-II, C-IV, D-III
• B. A-II, B-I, C-IV, D-III
• C. A-I, B-II, C-III, D-IV
• D. A-II, B-I, C-III, D-IV

Answer 1

The Correct Option is B

The correct answer is (B) : A-II, B-I, C-IV, D-III
$\Delta U=n{C}_v\Delta T$
For isothermal process $T$ is constant
So $\Delta U=0$
$A⟶II$
Adiabatic process
$\Delta Q=0$
$\Delta Q=\Delta U+\Delta W$
$\Delta U=-\Delta W$
Work done by gas is positive
So $\Delta U$ is negative
$\text{B}⟶\text{I}$
For Isochoric process $\Delta W=0$
$C⟶IV$
For Isobaric process
$\Delta W=P\Delta V\ne 0$
$\Delta U=n{C}_V\Delta T\ne 0$
Heat absorbed goes partly to increase internal energy and partly do work.