LIST I | LIST II | ||
A | Chlorophyll | 1 | \(Na _2 CO _3\) |
B | Soda ash | 2 | \(CaSO _4\) |
C | Dentistry, Ornamental work | 3 | \(Mg ^{2+}\) |
D | Used in white washing | 4 | \(Ca ( OH )_2\) |
To correctly match List I with List II, let's analyze each item:
A. Chlorophyll: - Chlorophyll contains magnesium (\( \text{Mg}^{2+} \)) as its central metal ion. - Match: A – III (\( \text{Mg}^{2+} \)).
B. Soda ash: - Soda ash is chemically sodium carbonate (\( \text{Na}_2\text{CO}_3 \)). - Match: B – I (\( \text{Na}_2\text{CO}_3 \)).
C. Dentistry, Ornamental work: - Calcium sulfate (\( \text{CaSO}_4 \)) is used in dentistry and ornamental work, especially in plaster form. - Match: C – II (\( \text{CaSO}_4 \)).
D. Used in white washing: - Slaked lime (\( \text{Ca(OH)}_2 \)) is commonly used in white washing. - Match: D – IV \(\text{Ca}(OH)_2\)
Conclusion: The correct matches are: \[ \text{A – III, B – I, C – II, D – IV} \]
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Match List-I with List-II.
Choose the correct answer from the options given below :