Match List I with List IILIST I LIST II A Chlorophyll 1 \(Na _2 CO _3\) B Soda ash 2 \(CaSO _4\) C Dentistry, Ornamental work 3 \(Mg ^{2+}\) D Used in white washing 4 \(Ca ( OH )_2\)
| LIST I | LIST II | ||
| A | Chlorophyll | 1 | \(Na _2 CO _3\) |
| B | Soda ash | 2 | \(CaSO _4\) |
| C | Dentistry, Ornamental work | 3 | \(Mg ^{2+}\) |
| D | Used in white washing | 4 | \(Ca ( OH )_2\) |
- A-III, B-I, C-II, D-IV
- A-II, B-III, C-IV, D-I
- A-III, B-IV, C-I, D-II
- A-II, B-I, C-III, D-IV
The Correct Option is A
Solution and Explanation
To correctly match List I with List II, let's analyze each item:
A. Chlorophyll: - Chlorophyll contains magnesium (\( \text{Mg}^{2+} \)) as its central metal ion. - Match: A – III (\( \text{Mg}^{2+} \)).
B. Soda ash: - Soda ash is chemically sodium carbonate (\( \text{Na}_2\text{CO}_3 \)). - Match: B – I (\( \text{Na}_2\text{CO}_3 \)).
C. Dentistry, Ornamental work: - Calcium sulfate (\( \text{CaSO}_4 \)) is used in dentistry and ornamental work, especially in plaster form. - Match: C – II (\( \text{CaSO}_4 \)).
D. Used in white washing: - Slaked lime (\( \text{Ca(OH)}_2 \)) is commonly used in white washing. - Match: D – IV \(\text{Ca}(OH)_2\)
Conclusion: The correct matches are: \[ \text{A – III, B – I, C – II, D – IV} \]
Top Questions on p -Block Elements
- Which one of these is the most acidic oxide?
- BCECE - 2025
- Chemistry
- p -Block Elements
- Which of these sulfides is not black?
- BCECE - 2025
- Chemistry
- p -Block Elements
- How many moles of O2 will be formed from the decomposition of Pb(NO3)2?
- BCECE - 2025
- Chemistry
- p -Block Elements
- Red lead is:
- BCECE - 2025
- Chemistry
- p -Block Elements
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:- JEE Main - 2025
- Chemistry
- p -Block Elements
Questions Asked in JEE Main exam
- Let \( [x] \) denote the greatest integer function, and let \( m \) and \( n \) respectively be the numbers of the points, where the function \( f(x) = [x] + |x - 2| \), \( -2<x<3 \), is not continuous and not differentiable. Then \( m + n \) is equal to:
- JEE Main - 2025
- Differential Equations
- Let \( f(x) = \frac{x - 5}{x^2 - 3x + 2} \). If the range of \( f(x) \) is \( (-\infty, \alpha) \cup (\beta, \infty) \), then \( \alpha^2 + \beta^2 \) equals to.
- JEE Main - 2025
- Functions
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
- The value of \( (\sin 70^\circ)(\cot 10^\circ \cot 70^\circ - 1) \) is:
- JEE Main - 2025
- Trigonometric Identities
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
- JEE Main - 2025
- Relations and functions
Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
- Group 15 Elements: Nitrogen family
- Group 16 Elements: Oxygen family
- Group 17 Elements: Fluorine family
- Group 18 Elements: Neon family