Question

Match List I with List II 

LIST I		LIST II
A	XeF4​	I	See-saw
B	SF4​	II	Square planar
C	NH4+​	III	Bent T-shaped
D	BrF3​	IV	Tetrahedral

Choose the correct answer from the options given below :

• A. A-IV, B-I, C-II, D-III
• B. A-II, B-I, C-III, D-IV
• C. A-II, B-I, C-IV, D-III
• D. A-IV, B-III, C-II, D-I

Hint:

Molecular shapes are determined by the VSEPR theory, which helps predict the geometry based on electron pairs and bond angles.

Answer 1

The Correct Option is C

Correct answer is (C): A-II, B-I, C-IV, D-III

Answer 2

• A. \( \text{XeF}_4 \) has a square planar structure.
• B. \( \text{SF}_4 \) has a see-saw shape.
• C. \( \text{NH}_4^+ \) has a tetrahedral geometry.
• D. \( \text{BrF}_3 \) has a bent T-shaped structure.

Thus, the correct matching is:

A-I, B-I, C-IV, D-III.

In this matching, the structures of various molecules are being analyzed based on the number of bonding pairs and lone pairs. The tetrahedral geometry of \( \text{NH}_4^+ \) is typical for molecules with four bonding pairs and no lone pairs. \( \text{BrF}_3 \), with its lone pairs, adopts a bent T-shaped structure, while \( \text{XeF}_4 \) adopts a square planar structure due to the presence of two lone pairs and four bonding pairs.