Question:
Match List-I with List-II
List-I
List-II
(A) Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l) (I) Primary battery (B) Zn(Hg)+HgO(s)→ZnO(s)+Hg(l) (II) Discharging of secondary battery (C) 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq) (III) Fuel cell (D) 2H2(g)+O2(g)→2H2O(l) (IV) Charging of
secondary battery
Choose the correct answer from the options given below:
Match List-I with List-II
List-I | List-II | ||
|---|---|---|---|
| (A) | Cd(s)+2Ni(OH)3(s)→CdO(s)+2Ni(OH)2(s)+H2O(l) | (I) | Primary battery |
| (B) | Zn(Hg)+HgO(s)→ZnO(s)+Hg(l) | (II) | Discharging of secondary battery |
| (C) | 2PbSO4(s)+2H2O(l)→Pb(s)+PbO2(s)+2H2SO4(aq) | (III) | Fuel cell |
| (D) | 2H2(g)+O2(g)→2H2O(l) | (IV) | Charging of secondary battery |
Choose the correct answer from the options given below:
Updated On: Feb 4, 2026
- (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
- (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
- (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
- (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
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The Correct Option is C
Solution and Explanation
From the given options the correct answer is option (C): (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
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Concepts Used:
P-Block Elements
- P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
- P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.
P block elements consist of:
- Group 13 Elements: Boron family
- Group 14 Elements: Carbon family
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- Group 18 Elements: Neon family