Match List I with List II.
List I List II A. Torque I. Nms–1 B. Stress II. Jkg–1 C. Latent Heat III. Nm D. Power IV Nm–2
Choose the correct answer from the options given below
Match List I with List II.
| List I | List II | ||
|---|---|---|---|
| A. | Torque | I. | Nms–1 |
| B. | Stress | II. | Jkg–1 |
| C. | Latent Heat | III. | Nm |
| D. | Power | IV | Nm–2 |
Choose the correct answer from the options given below
- A-III, B-II, C-I, D-IV
- A-III, B-IV, C-II, D-I
- A-IV, B-I, C-III, D-II
- A-II, B-III, C-I, D-IV
The Correct Option is B
Solution and Explanation
(A) Torque → (III) Nm
(B) Stress → (IV) N/m2
(C) Latent heat → (II) J/kg
(D) Power → (I) N m/s
So, the correct option is (B): A-III, B-IV, C-II, D-I
Top Questions on Stress and Strain
- A body of weight \( W \) is suspended from the ceiling of a room through a chain of weight \( w \). The ceiling pulls the chain by a force.
- KEAM - 2024
- Physics
- Stress and Strain
- Two blocks of mass \(2 \, \text{kg}\) and \(4 \, \text{kg}\) are connected by a metal wire going over a smooth pulley as shown in the figure. The radius of the wire is \(4.0 \times 10^{-5} \, \text{m}\) and Young's modulus of the metal is \(2.0 \times 10^{11} \, \text{N/m}^2\). The longitudinal strain developed in the wire is \(\frac{1}{\alpha \pi}\). The value of \(\alpha\) is _____. [Use \(g = 10 \, \text{m/s}^2\)]
- JEE Main - 2024
- Physics
- Stress and Strain
- A force is applied to a steel wire ' $A$ ', rigidly clamped at one end As a result elongation in the wire is $02\, mm$ If same force is applied to another steel wire ' $B$ ' of double the length and a diameter $24$ times that of the wire ' $A$ ', the elongation in the wire ' $B$ ' will be (wires having uniform circular cross sections)
- JEE Main - 2023
- Physics
- Stress and Strain
- The equivalent resistance between A and B is _________.
- JEE Main - 2023
- Physics
- Stress and Strain
The Young's modulus of a steel wire of length \(6 m\) and cross-sectional area \(3 \,mm ^2\), is \(2 \times 10^{11}\) \(N / m ^2\). The wire is suspended from its support on a given planet A block of mass \(4 kg\) is attached to the free end of the wire. The acceleration due to gravity on the planet is \(\frac{1}{4}\) of its value on the earth The elongation of wire is (Take \(g\) on the earth \(=10\, m / s ^2\)) :
- JEE Main - 2023
- Physics
- Stress and Strain
Questions Asked in JEE Main exam
- The work function of a metal 3eV. The colour of the visible light that is required to cause emission of photo electrons is:
- JEE Main - 2025
- Photoelectric Effect
- A force of 49 N acts tangentially at the highest point of a sphere (solid of mass 20 kg) kept on a rough horizontal plane. If the sphere rolls without slipping, then the acceleration of the center of the sphere is:
- JEE Main - 2025
- Quantum Mechanics
- The greatest value of \( n \), where \( n \in \mathbb{N} \), such that \( 3^n \) divides \( 50! \) is:
- JEE Main - 2025
- Number Systems
- For a short dipole placed at origin \( O \), the dipole moment \( P \) is along the \( x \)-axis, as shown in the figure. If the electric potential and electric field at \( A \) are \( V_0 \) and \( E_0 \) respectively, then the correct combination of the electric potential and electric field, respectively, at point \( B \) on the \( y \)-axis is given by:
- JEE Main - 2025
- Electrostatics
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
Concepts Used:
Stress Strain Curve
Stress:
The force applied per unit area in mechanics is understood as stress.
σ=FA
- σ is stress applied
- F is force applied
- A is that the area of force applied
- Stress is measured by unit N/m2
The ratio of internal force F that is produced when a substance is deformed, to the area A where force is applied is referred to as stress.
Strain:
Strain can be referred to as the ratio of the amount of deformation that the body experiences in the direction of force applied to the initial sizes of the body. The relation of deformation in terms of the length of the solid is shown below:
ε=δlL
where,
- ε = strain due to the stress applied
- δl = modified long
- L = the original length of the material
- Strain = the ratio for change of shape or size to the initial shape or size. It's expressed in numbers because it doesn't have any dimensions.
As strain defines the relative change in shape and it's a dimensionless quantity.
Explanation of Stress-Strain Curve:
The material's stress-strain curve delineates the connection between stress and strain for materials. In other words, a stress-strain curve is a graphical representation that shows the reaction of a material when a load is applied.