Question

Match List I with List II for the oxidation state of central atoms:

List I	List II
(A) Cr2O72−	(I) +3
(B) MnO4−	(II) +5
(C) VO3−	(III) +7
(D) FeF63−	(IV) +6

Choose the correct answer from the options given below:

• A. (A)- (I), (B)- (II), (C)- (III), (D)- (IV)
• B. (A)- (IV), (B)- (III), (C)- (II), (D)- (I)
• C. (A)- (I), (B)- (II), (C)- (IV), (D)- (III)
• D. (A)- (IV), (B)- (I), (C)- (III), (D)- (II)

Answer 1

The Correct Option is B

Based on the information given in the image, the correct answer is Option B. Here's a breakdown of the reasoning:

(A) Cr₂O₇²⁻ (Dichromate ion):

• The oxidation state of Cr in Cr₂O₇²⁻ is +6 (since the overall charge of the ion is -2 and the oxidation states of oxygens are -2).
• This matches Option II in List II.

(B) MnO₄⁻ (Permanganate ion):

• The oxidation state of Mn in MnO₄⁻ is +7 (since the overall charge of the ion is -1 and the oxidation states of oxygens are -2).
• This matches Option III in List II.

(C) VO₃⁻ (Vanadate ion):

• The oxidation state of V in VO₃⁻ is +5 (since the overall charge of the ion is -1 and the oxidation states of oxygens are -2).
• This matches Option II in List II.

(D) FeF₆³⁻ (Ferrate ion):

• The oxidation state of Fe in FeF₆³⁻ is +3 (since the overall charge of the ion is -3 and each fluorine has an oxidation state of -1).
• This matches Option I in List II.

Thus, the correct matching is Option B:
(A) - (IV), (B) - (III), (C) - (II), (D) - (I).