Question

In which compound does Mn (Manganese) have its highest oxidation state?

• A. MnO\(_2\)
• B. MnO\(_4\)
• C. KMnO\(_4\)
• D. Mn\(_2\)O\(_3\)

Hint:

The highest oxidation state of manganese is +7, seen in compounds like KMnO\(_4\) and MnO\(_4^-\). These are powerful oxidizing agents in redox chemistry.

Answer 1

The Correct Option is C

We will calculate the oxidation state of Mn in each compound: 
(1) MnO\(_2\): 
Let oxidation state of Mn be \( x \): \[ x + 2(-2) = 0 \Rightarrow x = +4 \] (2) MnO\(_4\): 
This is likely referring to the MnO\(_4^-\) ion. \[ x + 4(-2) = -1 \Rightarrow x = +7 \] (3) KMnO\(_4\): 
Potassium is +1, and each oxygen is -2: \[ +1 + x + 4(-2) = 0 \Rightarrow x = +7 \] (4) Mn\(_2\)O\(_3\): \[ 2x + 3(-2) = 0 \Rightarrow 2x = +6 \Rightarrow x = +3 \] So, the highest oxidation state is \( +7 \), which occurs in both MnO\(_4^-\) and KMnO\(_4\). Among the given named compounds, KMnO\(_4\) is the correct compound.