Question:

Magnetic susceptibility of Mg at 300 K is 5 1.2x10-5 . What is its susceptibility at 200 K ?

Updated On: Mar 29, 2025
  • 18x10-5
  • 180x10-5
  • 1.8x10-5
  • 0.18x10-5
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The Correct Option is C

Solution and Explanation

For paramagnetic substances, magnetic susceptibility \(\chi\) is inversely proportional to temperature \(T\) (Curie’s Law): \[ \chi \propto \frac{1}{T} \] Let \(\chi_1 = 1.2 \times 10^{-5}\) at \(T_1 = 300\,K\) We are to find \(\chi_2\) at \(T_2 = 200\,K\) Using Curie’s Law: \[ \frac{\chi_1}{\chi_2} = \frac{T_2}{T_1} \Rightarrow \frac{1.2 \times 10^{-5}}{\chi_2} = \frac{200}{300} = \frac{2}{3} \] \[ \chi_2 = \frac{1.2 \times 10^{-5} \times 3}{2} = 1.8 \times 10^{-5} \times 3 = 5.4 \times 10^{-5} \] Wait! There’s a mistake above — let's redo the correct way: \[ \chi_2 = \chi_1 \times \frac{T_1}{T_2} = 1.2 \times 10^{-5} \times \frac{300}{200} = 1.2 \times 10^{-5} \times 1.5 = 1.8 \times 10^{-5} \] Correction: The correct value is: \[ \chi_2 = 1.8 \times 10^{-5} \] So the correct answer is: (3) \(1.8 \times 10^{-5}\)

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