Solution: When m-chlorobenzaldehyde is treated with 50% KOH solution, it undergoes a reaction known as the Cannizzaro reaction, which occurs in aldehydes that do not have alpha hydrogens.
Cannizzaro Reaction: In the Cannizzaro reaction, an aldehyde is converted into a carboxylic acid and an alcohol in the presence of a strong base, like KOH. The reaction mechanism involves the disproportionation of the aldehyde, leading to the formation of the corresponding carboxylate and alcohol.
Reaction Process: For m-chlorobenzaldehyde, the reaction can be summarized as follows:
2 m-chlorobenzaldehyde + 50% KOH → m-chlorobenzoate + m-chlorobenzyl alcohol.
Final Products: The final products of the reaction are m-chlorobenzoate ion and m-chlorobenzyl alcohol.
Thus, the correct product obtained from the reaction is: chlorobenzoate and m-chlorobenzyl alcohol.
Convert Ethanal to But-2-enal
If all the words with or without meaning made using all the letters of the word "KANPUR" are arranged as in a dictionary, then the word at 440th position in this arrangement is:
If the system of equations \[ x + 2y - 3z = 2, \quad 2x + \lambda y + 5z = 5, \quad 14x + 3y + \mu z = 33 \] has infinitely many solutions, then \( \lambda + \mu \) is equal to:}
The equilibrium constant for decomposition of $ H_2O $ (g) $ H_2O(g) \rightleftharpoons H_2(g) + \frac{1}{2} O_2(g) \quad (\Delta G^\circ = 92.34 \, \text{kJ mol}^{-1}) $ is $ 8.0 \times 10^{-3} $ at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation ($ \alpha $) of water is _____ $\times 10^{-2}$ (nearest integer value). [Assume $ \alpha $ is negligible with respect to 1]