Solution: When m-chlorobenzaldehyde is treated with 50% KOH solution, it undergoes a reaction known as the Cannizzaro reaction, which occurs in aldehydes that do not have alpha hydrogens.
Cannizzaro Reaction: In the Cannizzaro reaction, an aldehyde is converted into a carboxylic acid and an alcohol in the presence of a strong base, like KOH. The reaction mechanism involves the disproportionation of the aldehyde, leading to the formation of the corresponding carboxylate and alcohol.
Reaction Process: For m-chlorobenzaldehyde, the reaction can be summarized as follows:
2 m-chlorobenzaldehyde + 50% KOH → m-chlorobenzoate + m-chlorobenzyl alcohol.
Final Products: The final products of the reaction are m-chlorobenzoate ion and m-chlorobenzyl alcohol.
Thus, the correct product obtained from the reaction is: chlorobenzoate and m-chlorobenzyl alcohol.
Ethanal to But-2-enal
Let \( y = f(x) \) be the solution of the differential equation
\[ \frac{dy}{dx} + 3y \tan^2 x + 3y = \sec^2 x \]
such that \( f(0) = \frac{e^3}{3} + 1 \), then \( f\left( \frac{\pi}{4} \right) \) is equal to:
Find the IUPAC name of the compound.
If \( \lim_{x \to 0} \left( \frac{\tan x}{x} \right)^{\frac{1}{x^2}} = p \), then \( 96 \ln p \) is: 32