Question:

m–chlorobenzaldehyde on treatment with 50\(\%\) KOH solution yields

Updated On: Nov 18, 2024
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The Correct Option is B

Solution and Explanation

Solution: When m-chlorobenzaldehyde is treated with 50% KOH solution, it undergoes a reaction known as the Cannizzaro reaction, which occurs in aldehydes that do not have alpha hydrogens.

Cannizzaro Reaction: In the Cannizzaro reaction, an aldehyde is converted into a carboxylic acid and an alcohol in the presence of a strong base, like KOH. The reaction mechanism involves the disproportionation of the aldehyde, leading to the formation of the corresponding carboxylate and alcohol.

Reaction Process: For m-chlorobenzaldehyde, the reaction can be summarized as follows:

2 m-chlorobenzaldehyde + 50% KOH → m-chlorobenzoate + m-chlorobenzyl alcohol.

Final Products: The final products of the reaction are m-chlorobenzoate ion and m-chlorobenzyl alcohol.

Thus, the correct product obtained from the reaction is: chlorobenzoate and m-chlorobenzyl alcohol.

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