The correct answer is (B):
log12 81 = p ⇒ log1234 = p
4log12 3=p
⇒ p/4 = log12 3
3(4-p/4+p)=3(1-p/4/1+p/4)
= 3(1-log12 3/log12+log12 3)
= 3(log(12/3)/log(12/3))
= 3log4/log36 = 3log36 4
= log68
The product of all solutions of the equation \(e^{5(\log_e x)^2 + 3 = x^8, x > 0}\) , is :